<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2//EN"> <HTML> <HEAD> <META HTTP-EQUIV="Content-Type" CONTENT="text/html; charset=iso-8859-1"> <META NAME="Generator" CONTENT="MS Exchange Server version 6.5.7638.1"> <TITLE>RE : dealing with mke2fs -T option</TITLE> </HEAD> <BODY>  To be complete, here is the way I made my calculus : I'm gonna write files of 32Mb each on a Xserve RAID with two "arrays" of 4.1Tb (sdd and sde). So, let me explain : 1/ 32Mb == 32768Kb 2/ on sdd with "-T news" : 1 inode = 4Kb --> 1 32Mb file is made of 8192 inodes 3/ on sde with "-T largefile4" : 1 inode = 4Mb --> 1 32Mb file is made of 8 inodes Then, as stated by 'df -i' : sdd contains 549437440 inodes --> 67070 files (8192 inodes per file) sde contains 1073120 inodes --> 134140 files (8 inodes per file) Where am I wrong ? Ionel -------- Message d'origine-------- De: Bryan Kadzban [<A HREF="mailto:bryan@kadzban.is-a-geek.net">mailto:bryan@kadzban.is-a-geek.net</A>] Date: dim. 27/05/2007 14:04 À: GARDAIS Ionel Cc: ext3-users@redhat.com Objet : Re: dealing with mke2fs -T option GARDAIS Ionel wrote: > Then I tried this : > $ dd if=/dev/zero of=/mount-sdx/file bs=4k count=8192 > for both /mount-sdd and /mount-sde > > Why don't I get "8192 inodes used" Because the FS creates one inode per file (unless you create a hard link, anyway), not one inode per X bytes. You only created one file here. ;-) </BODY> </HTML>