<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta content="text/html;charset=Big5" http-equiv="Content-Type"> <title></title> </head> <body bgcolor="#ffffff" text="#000000"> Les Mikesell wrote: <blockquote cite="mid45CB2D3D.5050500@gmail.com" type="cite"> <pre wrap=""><a class="moz-txt-link-abbreviated" href="mailto:edwardspl@ita.org.mo">edwardspl@ita.org.mo</a> wrote: </pre> <blockquote type="cite"> <blockquote type="cite"> <blockquote type="cite"> <pre wrap="">chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward </pre> </blockquote> <pre wrap="">You can use the symbolic form literally. I think it's easier to understand. Let the computer do the binary/octal math. g+rwx means add the read, write, and execute bits for the group. </pre> </blockquote> <pre wrap="">But I want to know what no of g+rwx... </pre> </blockquote> <pre wrap=""> The + means it is added to the bits already permitted. Look at them as groups of 3 bits in binary and take the octal value. user group other rwx rwx rwx You'll start with a home dir having rwx --- --- so that's 111 000 000 binary or 700 octal. Add the group rwx and you get 111 111 000 or 770 octal </pre> </blockquote> So, g+rwx = 770, right ?<br> <blockquote cite="mid45CB2D3D.5050500@gmail.com" type="cite"> <blockquote type="cite"> <blockquote type="cite"> <blockquote type="cite"> <pre wrap="">chmod +t ( What number of +t ) /home/edward </pre> </blockquote> </blockquote> </blockquote> <pre wrap=""> That's one more bit to the left, 1 000 000 000 binary, so 1000 octal. Add that to what you have. </pre> <blockquote type="cite"> <blockquote type="cite"> <pre wrap="">Same here, you can type it that way and it means add the "sticky" bit. </pre> </blockquote> <pre wrap="">Also want to know... </pre> </blockquote> <pre wrap=""> Altogether, the octal value for the mode ends up at 1770. But, as I said before the computer does a better job of thinking in octal. </pre> </blockquote> So, +t = 1770, right ?<br> <br> Edward.<br> </body> </html>