<html><head><style type="text/css"></style></head><body><div style="font-family:arial,helvetica,sans-serif;font-size:10pt">cat /proc/meminfo | awk '/MemTotal:/ { m = $2 f = m /= 1024 # Mb f /= 1024 # Gb } END {printf "%0.f\n", f }' on my machine I get 16 = 16 Gb <div style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"> <div style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"><hr size="1">From: Patrick Lists <ks-list@puzzled.xs4all.nl> To: jamesaharrisonuk@yahoo.co.uk; Discussion list about Kickstart <kickstart-list@redhat.com> Sent: Tue, December 21, 2010 8:10:07 AM Subject: Re: Detecting amount of memory? On 12/21/2010 01:39 PM, <a ymailto="mailto:jamesaharrisonuk@yahoo.co.uk" href="mailto:jamesaharrisonuk@yahoo.co.uk">jamesaharrisonuk@yahoo.co.uk</a> wrote: > The kernel reports the amount of memory in /proc/meninfo . It shows the memory information in kilobytes. > James > Sent from my Verizon Wireless BlackBerry Thank you for your suggestion James. I tried it out and /proc/meminfo seems to give the same amount of memory as free: $ grep "MemTotal" /proc/meminfo | awk '{ print $2 }' 6123716 Fortunately I did find some awk voodoo that works. For the archives here it is. Mind the line breaks. Line 2,3,4 should be all one line. mem=$(free|grep Mem|awk '{print$2}') echo "$mem" | awk '{ n = $0; sub(/[0-9]+(.[0-9]+)?/, ""); split(n, a, $0); n=a[1]; if ($0 == "G" || $0 == "") { n *= 1024 }; if (/^kB?/) { n /= 1024 }; printf "%d\n", n }' # Intentionaly round to an integer This line gives 6144 on a box with 6GB mem. Regards, Patrick [snip] </div></div> </div> </body></html>