<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"> <html><body> <p>Hi,</p> <p>Just wanted to "bump" this back up the top in case anyone may know how to do this but didn't see it the first time around :) Surely there's some way of properly testing watchdog instead of just taking its word for it.</p> <p> </p> <p>On 06.09.2012 17:40, Russell Jones wrote:</p> <blockquote type="cite" style="padding-left:5px; border-left:#1010ff 2px solid; margin-left:5px; width:100%"> <pre>CentOS 6 Hi all, I am working on setting up sanlock + watchdog on a 2 node KVM pair. Sanlock is working beautifully and is preventing access to the VM disks by more than one process as it should across both boxes. I am attempting to test failure scenarios involving watchdog, but I am having a hard time getting it to actually reset the server. I am running wdmd with -D so I can see the register requests. When I start sanlock with "service sanlock start" I can see it talk to the wdmd process, as debug logs "register ............ sanlock_daemon". I then send a "kill -9" signal to the daemon to try to simulate a crash, and wdmd logs "client_pid_dead". I would expect Watchdog to see that the PID is dead and as a result start the timer and reboot the server. It does not do that however. Am I misunderstanding how it reacts to TERM requests? How can I properly test wdmd? Thanks for the help! _______________________________________________ libvirt-users mailing list <a href="mailto:libvirt-users@redhat.com">libvirt-users@redhat.com</a> <a href="https://www.redhat.com/mailman/listinfo/libvirt-users">https://www.redhat.com/mailman/listinfo/libvirt-users</a> </pre> </blockquote> <div> </div> </body></html>