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<div class="moz-cite-prefix">Hi Dan. May I ask a question? Is your
security team looking for a fix to a specific security problem or
CVE or are they asking that you run the latest version as a rule?<br>
<br>
thanks,<br>
Brian<br>
<br>
On 06/29/2017 11:24 AM, Davis, Daniel (NIH/NLM) [C] wrote:<br>
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<p class="MsoNormal"><span style="font-size:14.0pt">I’ve been
lurking on this list for a while, and I wanted to bring
myself up to date. I noticed some talk of a community SCL
for a “latest” Python, which would be a non-patched pure
build of Python that is kept up-to-date by the community.
Where is that at? Who is leading it? How can I help?<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:14.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:14.0pt">For
background, we’ve used rh-python34 for some time, but our
security team recently dinged us for sticking with Python
3.4.2, and my DevOps team (who have less time due to
tickets), just recompiled Python 3.4.6 blind to get past the
security problem. I would have argued we should move to
rh-python35, but that would eventually suffer the same
problem. What we need is a distribution that keeps up to
date, but is still distributed as an rpm.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:14.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:14.0pt">Thanks,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:14.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal">Dan Davis, Systems/Applications Architect
(Contractor),<o:p></o:p></p>
<p class="MsoNormal">Office of Computer and Communications
Systems,<o:p></o:p></p>
<p class="MsoNormal">National Library of Medicine, NIH<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
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<pre wrap="">_______________________________________________
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<pre class="moz-signature" cols="72">--
Brian Gollaher
Red Hat Platform Product Management
Phone: 978 392-3173
Cell: 508 740-6549
<a class="moz-txt-link-abbreviated" href="mailto:briang@redhat.com">briang@redhat.com</a></pre>
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