[PATCH 1/6] jbd: remove duplicated debug print

Akinobu Mita mita at miraclelinux.com
Sat Sep 10 14:36:04 UTC 2005


On Fri, Sep 09, 2005 at 02:16:49PM -0400, Theodore Ts'o wrote:
> On Fri, Sep 09, 2005 at 05:43:42PM +0900, Akinobu Mita wrote:
> > remove duplicated debug print
> 
> > -	jbd_debug(3, "JBD: commit phase 2\n");
> > -
> 
> If you're going to do this, please renumber the rest of the "commit
> phase n" messages.  Or the debugging messages will look very funny.

The second duplicated "commit phase 2" only does:

 	J_ASSERT (commit_transaction->t_sync_datalist == NULL);

So I thought it might be accidentaly inserted.
diff -U 9 :

--- ./fs/jbd/commit.c.orig	2005-09-10 22:09:05.000000000 +0900
+++ ./fs/jbd/commit.c	2005-09-10 22:09:25.000000000 +0900
@@ -419,20 +419,18 @@ write_out_data:
 		cond_resched_lock(&journal->j_list_lock);
 	}
 	spin_unlock(&journal->j_list_lock);
 
 	if (err)
 		__journal_abort_hard(journal);
 
 	journal_write_revoke_records(journal, commit_transaction);
 
-	jbd_debug(3, "JBD: commit phase 2\n");
-
 	/*
 	 * If we found any dirty or locked buffers, then we should have
 	 * looped back up to the write_out_data label.  If there weren't
 	 * any then journal_clean_data_list should have wiped the list
 	 * clean by now, so check that it is in fact empty.
 	 */
 	J_ASSERT (commit_transaction->t_sync_datalist == NULL);
 
 	jbd_debug (3, "JBD: commit phase 3\n");




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