How to compare file size in script?

[Hongwei Li]

> Hongwei Li wrote:
>> Hi,
>>
>> I want to write a script to compare file sizes.  My script is like this:
>>
>> #!/bin/sh
>> ls -l /tmp/test/t1 | awk '{print $5}' > thesize
>> echo `cat thesize`
>> if [ `cat thesize` > 300000 ]
>> then
>>         echo "big file: thesize"
>>         exit 0
>> fi
>>
>> But, no matter how small or big the file t1 is, it always display:
>>
>> 11190
>> big file: thesize
>>
>> The actual size of t1 is 11190.  I also tried the other code:
>>
>> #!/bin/sh
>> thissize=`ls -l /tmp/test/t1 | awk '{print $5}'`
>> echo "$thissize"
>> if [ $thissize > 300000 ]
>> then
>>         echo "big file: $thissize"
>>         exit 0
>> fi
>>
>> then, it displays:
>>
>> 11190
>> big file: 11190
>>
>> What's wrong in the codes?  How to fix it?
>
> "man test" reveals that the comparison you want is "-gt", not ">", which
> will redirect output into a file called 300000 in this case.
>
> Paul.
>
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>

Thank you!  It works now.

Hongwei