mp3 to audio CD

Paul Smith phhs80 at gmail.com
Fri Dec 9 11:50:30 UTC 2005


On 12/8/05, Nix, Robert P. <Nix.Robert at mayo.edu> wrote:
> >     wavfile=`echo $file | sed -e "s/mp3/wav/g"`
>
> For what it's worth,
> $ echo lamp3.mp3 | sed -e "s/mp3/wav/g"
> lawav.wav
> which is probably not what's required.
>
> $ file="bright lamp3.mp3"
> $ wavfile="$(basename "$file" .mp3).wav"
> $ echo $wavfile
> bright lamp3.wav
>
> Still doesn't help if someone calls a file "Windows User.MP3". If that's
> a problem, then you probably do want to revert to sed:
> $ echo lamp3.MP3 | sed -e "s/[Mm][Pp]3$/wav/g"
> lamp3.wav
> ------end snip---------
>
> Another solution would be:
>   wavfile=`echo $file | sed -e "s/\.mp3/.wav/g"
>
> This works for the lamp3.mp3 example. It wouldn't work as well for lamp.mp3file.mp3

I would like to add the following: the line

lame $file $wavfile

should be replaced with

lame "$file" "$wavfile"

so that the script works fine when there are file names like

01\ -\ Supertramp\ -\ School.mp3

Paul




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