GRUB and the last FC4 kernel
Hoffmann
oasf2004 at yahoo.com
Tue Jul 5 00:40:23 UTC 2005
--- Mike McCarty <mike.mccarty at sbcglobal.net> wrote:
> Hoffmann wrote:
>
> >--- Paul Howarth <paul at city-fan.org> wrote:
> >
> >
> >
> >>On Mon, 2005-07-04 at 13:15 -0700, Hoffmann wrote:
> >>
> >>
> [snip]
>
> >>>/boot/, eg.
> >>># root (hd0,2)
> >>># kernel /vmlinuz-version ro
> >>>root=/dev/VolGroup00/LogVol00
> >>># initrd /initrd-version.img
> >>>#boot=/dev/hda
> >>>default=2
> >>>y
> >>>
> This says to boot entry number 2 by default.
>
> >>>timeout=10
> >>>splashimage=(hd0,2)/grub/splash.xpm.gz
> >>>hiddenmenu
> >>>title Fedora Core (2.6.12-1.1387_FC4)
> >>>
> This is entry 0.
>
> >>> root (hd0,2)
> >>> kernel /vmlinuz-2.6.12-1.1387_FC4 ro
> >>>root=/dev/VolGroup00/LogVol00 rhgb quiet
> >>> initrd /initrd-2.6.12-1.1387_FC4.img
> >>>title Fedora Core (2.6.11-1.1369_FC4)
> >>>
> >>>
> This is entry 1.
>
> >>> root (hd0,2)
> >>> kernel /vmlinuz-2.6.11-1.1369_FC4 ro
> >>>root=/dev/VolGroup00/LogVol00 rhgb quiet
> >>> initrd /initrd-2.6.11-1.1369_FC4.img
> >>>title Windows
> >>>
> >>>
> This is entry 2, the default.
>
> >>> rootnoverify (hd0,1)
> >>> chainloader +1
> >>>title Other
> >>>
> >>>
> This is entry 3.
>
> >>> rootnoverify (hd0,0)
> >>> chainloader +1
> >>>
> >>>
> >>"rpm -e kernel-2.6.11-1.1369_FC4" should be fine.
> >>
> >>
> >
> >
> [snip]
>
> >Hi Paul,
> >
> >Many thanks. I uninstalled the precious FC4 kernel
> >sucessfuly, and now I have just the new FC4 kernel
> and
> >my windows partiction. All is fine.
> >However, I didn't understood the logic of the
> >'changing number' you mentioned above.
> >Could you, please, explain me again?
> >Thanks!
> >Hoffmann
> >
> >
> When you commented entry # 2, then the next entry,
> "Other"
> moved up from being entry #3 to being entry #2, the
> default.
>
> Mike
>
> --
>
p="p=%c%s%c;main(){printf(p,34,p,34);}";main(){printf(p,34,p,34);}
> This message made from 100% recycled bits.
> I can explain it for you, but I can't understand it
> for you.
> I speak only for myself, and I am unanimous in that!
>
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>
Hi Mike:
Now got it the logic.
The reason for my 'stupid' question is that I thought
that:
(hd0,0) would mean entry 0
(hd0,1) would mean entry 1
(hd0,2) would mean entry 2, and so on.
Many thanks!
Best,
Hoffmann
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