xargs +sed question
Amadeus W. M.
amadeus84 at verizon.net
Thu Dec 7 03:19:32 UTC 2006
On Wed, 06 Dec 2006 21:36:54 -0500, Matthew Miller wrote:
> On Thu, Dec 07, 2006 at 02:31:56AM +0000, Amadeus W. M. wrote:
>> I'd normally ask this in comp.os.linux.misc, but my news server is not
>> responding, so I'm asking it here.
>> I have a bunch of files in a directory tree in which I want to replace a
>> string A with string B. I'm trying to do this with xargs like so:
>> grep -ri -l A . | xargs sed -e 's/A/B/g'
>> and this does what I want, except, of course, that it outputs everything
>> to stdout. Is there any way to pass the name of each input file as
>> output for sed?
>
> You want the "sed -i" option, which edits files in place. (I believe this is
> a GNU extension.)
>
>
> --
> Matthew Miller mattdm at mattdm.org <http://mattdm.org/>
> Boston University Linux ------> <http://linux.bu.edu/>
>
Worked beautifully, thanks!
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