quick script question

[Mikkel L. Ellertson]

M E Fieu wrote:
> Hi.. Need to ask you a simple script question,  I used the date command to get the yesterday web
> log file using the following command echo ex`date -d yesterday +%y%m%d.log`  in Linux.  I want to
> create a simple script to cat /home/IT/ex060530.log > kr.log using the following script but it is
> not working.  May I know how do I put the output of echo ex`date -d yesterday +%y%m%d.log into cat
> /home/IT/xxxx  > kr.log ?
> 
> [root at w2 krweblog3]# echo ex`date -d yesterday +%y%m%d.log`
> ex060530.log
> 
> [root at w2 krweblog3]# vi krweblog.sh
> 
> #!/bin/sh
> #
> KRWEBLOG3= echo ex`date -d yesterday +%y%m%d.log`
> cat /home/IT/$KRWEBLOG3 > kr.log
> 
For thing like this, I like to use something like:

KRWEBLOG=$(date -d yesterday +ex%y%m%d.log)
cat /home/IT/$KRWEBLOG3 > kr.log

KRWEBLOG will have the value of ex060530.log if I ran it now on my
system. Enclosing a command inside $() returns the output of the
command. You could also use:
KRWEBLOG=`date -d yesterday +ex%y%m%d.log`
but I find the $() format easyer to read.

Mikkel
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