SAMBA PROBLEM

Craig White craigwhite at azapple.com
Wed Sep 20 15:01:53 UTC 2006


On Wed, 2006-09-20 at 09:06 -0500, Randy Easley wrote:

> __________________________________________________________________________________________________________________________
> 
> 
> On Tue, 2006-09-19 at 16:29 -0500, Randy Easley wrote:
> 
> > I cannot print from a winXp machine to a Fedora server? Smb.conf
> has 
> 
> > public = yes and guest ok = yes. On the same workgroup with no
> domain. 
> 
> > I can clearly see the file shares which are also public.
> 
> > Log files show WERR_ACCESS_DENIED over and over. 
> 
> > 
> 
> ----
> 
> make sure that the 'user' printing (there is a user even if it is a
> 'guest' - it would be whichever user guest is being mapped to) has
> write privileges to the 'spool' directory that you created in smb.conf
> 
> see
> 
> http://samba.org/samba/docs/man/Samba-HOWTO-Collection/CUPS-printing.html#cups-exam-simple
> 
> in the example shown above...
> 
> chmod 777 /var/spool/samba -R
----
I do not understand? (Ignorance) 
> 
> If you have public and guest set to yes why couldn’t ANY windows PC
> print to a linux printer? Here is the error in smbd.log
> 
> Printing/nt_printing.c:nt_printing_init(383)
> 
> nt_printing_init: error checking published printers:
> WERR_ACCESS_DENIED
> 
> Thanks again
----
Because all of samba activities are mapped to a specific user - even
those of 'public' or 'guest' are mapped to a posix (Linux in this
instance) account.

You can verify this by doing...

testparm -sv |grep guest

It should point out that even if it isn't configured in smb.conf, by
default 'guest' is mapped to a 'nobody' account which by default isn't
likely to have write access to your print spool directory for samba
which is why access is going to be denied.

I suppose you can either continue to not understand or try the
suggestion that I offered or even better yet, read through the
documentation in the link I provided - the official Samba How To - which
allows you to understand all of this for yourself.

Craig




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