[Fwd: User account ( hacked ) of FC6 System]
Les Mikesell
lesmikesell at gmail.com
Thu Feb 8 14:01:33 UTC 2007
edwardspl at ita.org.mo wrote:
>>> chmod g+rwx ( What number of g+rwx, eg : ?77 ) /home/edward
>>
>> You can use the symbolic form literally. I think it's easier to
>> understand. Let the computer do the binary/octal math.
>> g+rwx means add the read, write, and execute bits for the group.
>
> But I want to know what no of g+rwx...
The + means it is added to the bits already permitted. Look at them as
groups of 3 bits in binary and take the octal value.
user group other
rwx rwx rwx
You'll start with a home dir having rwx --- --- so that's 111 000 000
binary or 700 octal.
Add the group rwx and you get 111 111 000 or 770 octal
>>> chmod +t ( What number of +t ) /home/edward
That's one more bit to the left, 1 000 000 000 binary, so 1000 octal.
Add that to what you have.
>> Same here, you can type it that way and it means add the "sticky" bit.
>
> Also want to know...
Altogether, the octal value for the mode ends up at 1770. But, as I
said before the computer does a better job of thinking in octal.
>>> chown root /home/edward/ All_dot_filenames
>>
>> Don't get carried away with wildcards on this one. .* will also match
>> .. which is your parent directory.
>>
> ok,
> chown root /home/edward/.*
I meant not to do that. In this case it won't break anything because
the parent (..) dir of /home/edward will alread be owned by root, but it
is a bad idea in general to wildcard .*
--
Les Mikesell
lesmikesell at gmail.com
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