Sed programming question
Kevin Martin
kevintm at ameritech.net
Fri Dec 12 15:22:29 UTC 2008
Dan Thurman wrote:
> Kevin Martin wrote:
>>
>> Gordon Messmer wrote:
>>
>>> Dan Thurman wrote:
>>>
>>>> I tested your suggestion above with and without -r option
>>>> but could not make it work as an "AND operator":
>>>>
>>>> # echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}'
>>>> goo har
>>>>
>>> $ rpm -q sed
>>> sed-4.1.5-11.fc10.x86_64
>>>
>>> $ echo "foo har" | sed -re '/foo/{/bar/{s/foo/goo/}}'
>>> foo har
>>>
>>>
>>
>> $ echo "foo har" | sed -e "s/foo/goo/g" -e "s/har/bar/g"
>> goo bar
>>
>> Is this what you're trying to do?
>>
>> Kevin
>>
> No. The result should be: (foo AND har) = (1&0)=0
> so the inside nested brackets should not be allowed to
> run and the original string (foo har) is returned.
>
> Dan
>
Ah, I missed the first part of the conversation where it was explained
what you were doing (ah, snipped mail). Sorry for butting in.
Kevin
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