linux auditd: Not getting log for chmod syscall
Marcelo Cerri
mhcerri at linux.vnet.ibm.com
Wed Jan 18 12:10:39 UTC 2012
Just remove the quotes. It's only necessary when running auditctl
directly from bash.
Regards,
Marcelo
On 01/18/2012 09:10 AM, bharat gupta wrote:
> when i am using auid>=500 in quote like u have told -a always,exit -F
> arch=b64 -S chmod -S fchmod -S fchmodat -F
> 'auid>=500' -F auid!=4294967295 -k perm_mod
>
> it is giving error :
> #service auditd restart
> Stopping auditd: [ OK ]
> Starting auditd: [ OK ]
> -F unknown field: "auid
> There was an error in line 102 of /etc/audit/audit.rules
>
>
>
> On Sat, Jan 14, 2012 at 1:34 AM, Steve Grubb <sgrubb at redhat.com
> <mailto:sgrubb at redhat.com>> wrote:
>
> On Thursday, January 12, 2012 11:52:29 PM bharat gupta wrote:
> > I am using redhat 6, and trying to create logs for some system
> call using
> > the rule given below:
> >
> > *-a always,exit -F arch=b64 -S chmod -S fchmod -S fchmodat -F
> auid>=500
> > -F auid!=4294967295 -k perm_mod*
>
> The rule works for me.
>
> # auditctl -a always,exit -F arch=b64 -S chmod -S fchmod -S
> fchmodat -F
> 'auid>=500' -F auid!=4294967295 -k perm_mod
>
> I don't have any asterisk and I have single quote marks since bash
> will
> interpret the > as a redirection. But then doing a chmod command,
> it does pick
> up the fchmodat() syscall.
>
>
> > After running command chmod i was not able to get any log, but
> when i used
> > strace command i have seen that syscall have been called.
> > I also checked that auditd service is running properly.
>
> When you use auditctl -l, is the rule just like you expected?
>
> LIST_RULES: exit,always arch=3221225534 (0xc000003e) auid>=500
> (0x1f4) auid!=-1
> (0xffffffff) key=perm_mod syscall=chmod,fchmod,fchmodat
>
> It should just work unless you are on a distribution that does not
> really
> support auditing.
>
> -Steve
>
>
>
>
> --
> Bharat Gupta
> IIT -Roorkee
>
>
>
> --
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