[linux-lvm] about to give up
Gonyou, Austin
austin at coremetrics.com
Wed Jul 11 15:30:10 UTC 2001
perhaps just blowing away your VG, then re-setting the volumes as PVs in
that vg, then growing them one at a time?
--
Austin Gonyou
Systems Architect, CCNA
Coremetrics, Inc.
Phone: 512-796-9023
email: austin at coremetrics.com
> -----Original Message-----
> From: Eli Criffield [mailto:eli at zendo.net]
> Sent: Wednesday, July 11, 2001 8:30 AM
> To: linux-lvm at sistina.com
> Subject: [linux-lvm] about to give up
>
>
>
> Well I've run out of things to try and am about to start the
> process of
> reinstalling everything. But i thought I'd give it one last
> try to see if
> anyone had any ideas?
>
> The story goes, I have three partitions on one hard drive
> /dev/hda1 (a 30
> meg /boot) /dev/hda2, and /dev/hda3 are both LVM.
>
> /dev/hda3 was the only LVM partition. I vgextened to include
> /dev/hda2,
> then rebooted and now vgscan finds no volume groups.
>
> pvscan only shoes that /dev/hda3 is part of a volume group
> and doesn't see
> anything about /dev/hda2
>
> uud_fixer gives me
> #./uuid_fixer /dev/hda2 /dev/hda3
> /dev/hda2 - pv_read{}: PV identifier invalid
>
> but if i run it just against /dev/hda3 i get
> #./uuid_fixer /dev/hda3
> Error: number of PVs passed in does not match number of PVs
> in /dev/hda3s
> VG
>
> 1 PVs where passed in and 2 where expected
>
> #pvdata -U /dev/hda2 gives
> pvdata -- ERROR "pv_read{}: PV identifier invalid" reading
> physical volume
> uuid list from physical volume "/dev/hda2"
>
> #pvdata -U /dev/hda3 gives
> --- List of physical volume UUIDs ---
>
>
>
> 000: elhLXoMw5J8qaEgN2DzEYoWoqhqH7H5a
>
> 001: 9AoOf5F6c58dcyJ30pfwNp153TI5PjLF
>
>
> So /dev/hda2 has no information about being in volumegroup rootvg but
> rootvg thinks it is, or at least thats as near as i can tell what's
> wrong. Is there some way to remove /dev/hda2 from the volume
> group even if
> i can't find it with vgscan. Is there some way to change
> /dev/hda2 so it
> thinks there it is part of the volume group?
>
>
> Thanks again for any help
>
>
> eli
>
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