[linux-lvm] Why does thinpool take 2*poolmetadatasize space?
Scott Moser
smoser at brickies.net
Tue Oct 20 16:33:41 UTC 2020
When I create an lvmthinpool with size S and poolmetadatasize P,
it reduces the available freespace by S+2P. I expected that to
be S+P. Where did the extra poolmetadatasize get used?
See below for example.
before lvcreate we had 255868 free, after we had 254588.
The difference is 1280. (1024 + 2*128).
# lvm vgcreate --metadatasize=128m myvg0 /dev/vda
Physical volume "/dev/vda" successfully created.
Volume group "myvg0" successfully created
# pvs --unit=m
PV VG Fmt Attr PSize PFree
/dev/vda myvg0 lvm2 a-- 255868.00m 255868.00m
# vgs --unit=m
VG #PV #LV #SN Attr VSize VFree
myvg0 1 0 0 wz--n- 255868.00m 255868.00m
# lvm lvcreate --ignoremonitoring --yes --activate=y \
--setactivationskip=n --size=1024m --poolmetadatasize=128m \
--thinpool=mythinpool myvg0
Thin pool volume with chunk size 64.00 KiB can address at most 15.81 TiB of da
ta.
Logical volume "mythinpool" created.
# vgs --unit=m
VG #PV #LV #SN Attr VSize VFree
myvg0 1 1 0 wz--n- 255868.00m 254588.00m
# lvs --all --unit=m
LV VG Attr LSize Pool Origin Data%
Meta% Move Log Cpy%Sync Convert
[lvol0_pmspare] myvg0 ewi------- 128.00m
mythinpool myvg0 twi-a-tz-- 1024.00m 0.00 10.03
[mythinpool_tdata] myvg0 Twi-ao---- 1024.00m
[mythinpool_tmeta] myvg0 ewi-ao---- 128.00m
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