sort

[vipin sagar]

Mr.Sean is correct.

...a litle bit from my side...

[vipin at vipin ~]$ grep -v age testsort.txt | awk '{print $2}' | sort -r


On 6/19/06, Miner, Jonathan W (CSC) (US SSA)
<jonathan.w.miner at baesystems.com> wrote:
>
>
>         -----Original Message-----
>         From: redhat-list-bounces at redhat.com on behalf of Aimin Yan
>         Sent: Sat 06/17/2006 02:23 PM
>         To: redhat-list at redhat.com
>         Cc:
>         Subject: sort
>
>
>
>         i have a file, I want to sort this file based on the 2nd column, and start
>         from 1st row.how can
>         I do use sort command to do in redhat linux.
>         for example, this is file I want to sort
>
>
>         name  age  income
>         trorry   34    344
>         aimin   36    345
>         shihe   23    3667
>
>         Aimin
>
>         -----------------------------
>
>         Lots of possible answers to this, here is one that preserves the header line, and the rest of the file contents:
>
>         f={filename}
>
>         (head -1 $f; awk 'BEGIN {getline} {print $0}' $f | sort -k2 -n) > $f.new
>
>         mv $f.new $f
>
>
>
>         This depends on having a single title line in the field, a better method, in my opinion, is to use the pound sign (#) to mark comments.  The code then becomes:
>
>         f={filename}
>
>         (grep '^#' $f; grep -v '^#' $f | sort -k2 -n) > $f.new
>
>         mv $f.new $f
>
>
>
>         Enjoy
>
>
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>


-- 
~O_0~
~sagar
http://vipinsagar.be
...i've to look back when i heard a gong! i could only see a huge
cobweb and its shining, just got wonder, what the time it was…5AgAr