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Re: sort



Mr.Sean is correct.

...a litle bit from my side...

[vipin vipin ~]$ grep -v age testsort.txt | awk '{print $2}' | sort -r


On 6/19/06, Miner, Jonathan W (CSC) (US SSA)
<jonathan w miner baesystems com> wrote:


        -----Original Message-----
        From: redhat-list-bounces redhat com on behalf of Aimin Yan
        Sent: Sat 06/17/2006 02:23 PM
        To: redhat-list redhat com
        Cc:
        Subject: sort



        i have a file, I want to sort this file based on the 2nd column, and start
        from 1st row.how can
        I do use sort command to do in redhat linux.
        for example, this is file I want to sort


        name  age  income
        trorry   34    344
        aimin   36    345
        shihe   23    3667

        Aimin

        -----------------------------

        Lots of possible answers to this, here is one that preserves the header line, and the rest of the file contents:

        f={filename}

        (head -1 $f; awk 'BEGIN {getline} {print $0}' $f | sort -k2 -n) > $f.new

        mv $f.new $f



        This depends on having a single title line in the field, a better method, in my opinion, is to use the pound sign (#) to mark comments.  The code then becomes:

        f={filename}

        (grep '^#' $f; grep -v '^#' $f | sort -k2 -n) > $f.new

        mv $f.new $f



        Enjoy


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