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RE: Quick question on awk usage



 

> -----Original Message-----
> From: redhat-list-bounces redhat com 
> [mailto:redhat-list-bounces redhat com] On Behalf Of Bliss, Aaron
> Sent: Tuesday, June 27, 2006 11:03 AM
> To: redhat-list redhat com
> Subject: RE: Quick question on awk usage
> 
> Sorry, $14 == 528, not $12 (looks like the email client 
> wrapped the line
> also)
> 
> Aaron 
> 
> Hi everyone, I have a quick question on using awk from the 
> command line; I have a tab delimited file, and would like to 
> know the syntax to print the entire line only when $12 == 
> 575; the syntax from the command line to print only $1 would 
> be cat security.log | awk '{print $1}' ; any ideas (grepping 
> for 578 won't be good enough since it's possible that
> 578 could appear somewhere else in the file)  Thanks very much.
> 
> Aaron
> 
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog      4
> Security        263985  Sun Jun 25 15:54:02 2006        528
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog      4
> Security        263985  Sun Jun 25 15:54:02 2006        575          
> 
> 

I believe this should do it:

awk ' $14 == 575 {print $0}'

Michael



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