sed regular expression help

[Davis, Brent]

Yea sorry about that.  My co-worker mentioned that the underlined wouldn't come through.

The '+%D'` is what I had underlined.

I thought I had tried the regex before and it didn't work.  I just tried it again, and same thing.



sed -e "s/\'\W%D\'\`//g;/skipping/d"


BEFORE.....: `date --date=2015-01-10 '+%D'`
AFTER......: `date --date=2015-01-01 '+%D'`







-----Original Message-----
From: redhat-list-bounces at redhat.com [mailto:redhat-list-bounces at redhat.com] On Behalf Of Joshua Gimer
Sent: Thursday, May 21, 2015 5:26 PM
To: General Red Hat Linux discussion list
Subject: Re: sed regular expression help

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Another slash?

s/match regex/replace value/options

s/\'\W%D\'\`//g

Also I didn't see anything underlined in your email. Need clarification on what you are trying to remove, to fully assist.

Thanks,
Josh

On Thursday, May 21, 2015, Davis, Brent <Brent.Davis at sscgp.com> wrote:

> I am still getting into regular expressions so I am still somewhat 
> fresh, but I am stuck on a particular expression.  I use the 
> regexr.com site, which is extremely helpful to test, and I have 
> bounced off other forums but everything I try I can't get this 
> expression to work.  For any seasoned people out there, this will probably be quick and dirty.
>
>
> I want to filter out the following characters underline: BEFORE.....:
> `date --date=2015-01-10 '+%D'`
>
> The expression I have built is sed -e "/\'\W%D\'\`/g".  I get no 
> errors or anything, but my output still has the characters in 
> underline.  I have tried sed -e "/[']\W%D['][`]/g", still the same 
> thing.  No errors but the characters are still there.  Like I said, I 
> tested this on regexr.com, and either works no problem.  Any ideas out there?
>
> Thanks
> Brent
>
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--
Thanks,
Joshua Gimer

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