[libvirt] [PATCH v2 1/3] qemu: use a bigger unplug timeout for PPC64 guests

Cole Robinson crobinso at redhat.com
Wed Oct 9 20:15:23 UTC 2019


On 9/11/19 5:05 PM, Daniel Henrique Barboza wrote:
> For some architectures and setups, device removal can take
> longer than the default 5 seconds. This results in commands
> such as 'virsh setvcpus' to fire timeout messages even if
> the operation were successful in the guest, confusing the
> user.
> 
> This patch sets a new 10 seconds unplug timeout for PPC64
> guests. All other archs will keep the default 5 seconds
> timeout.
> 
> Instead of putting 'if PPC64' conditionals inside qemu_hotplug.c
> to set the new timeout value, a new QEMU driver attribute
> 'unplugTimeout' was added. The timeout value is set during
> qemuStateInitialize only once. All qemu_hotplug.c functions
> that uses the timeout have easy access to a qemu_driver object,
> thus the change to use unplugTimeout is straightforward.
> 
> The now unused 'qemuDomainRemoveDeviceWaitTime' global can't
> be simply erased from qemu_hotplug.c though. Next patch will
> remove it properly.
> 

Sorry for the wrong review delay. I see this implements danpb's 
suggestion from the previous thread. The implementation seems a little 
odd to me though because it is differentiating on host arch, but this is 
about guest arch right? And probably an arbitrary number of options, 
like I imagine TCG would want a longer timeout too (though that's not 
anything you need to deal with)

So I think this should be a function that lives in qemu_hotplug.c and 
acts on a DomainDef at least. The test suite will have to mock that in a 
qemuhotplugmock.c file, tests/qemucpumock.c is a good example to follow.

If you do that as an upfront patch, it can go in first. Then add the ppc 
changes in an add on patch.

You can CC me on the next version and I will review it

Thanks,
Cole




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